(vii) log32 8=m
Again please

Answer:
log_(32)8= 3/5
Step-by-step explanation:
Log_(32)8 = m
write is as
32^m=8
(2^5)^m = 2^3
2^5m = 2^3
Since the bases are the same, then two expressions are only equal if the exponents are also equal.
5m = 3
divide 5 on both sides to remove it from m
m= 3/5
Hope this helps!
The value of m is [tex]\frac{3}{5}[/tex].
'Logarithm is the exponent or power to which a base must be raised to yield a given number.'
According to the given problem,
⇒ [tex]log_{32}8[/tex] = m
⇒ m = [tex]log_{32}8[/tex]
⇒ m = [tex]\frac{log 8 }{log32}[/tex]
⇒ m = [tex]\frac{log(2)^{3} }{log(2)^{5} }[/tex]
⇒ m = [tex]\frac{3log2}{5log2}[/tex]
⇒ m = [tex]\frac{3}{5}[/tex]
Hence, we can conclude, the value of m is [tex]\frac{3}{5}[/tex].
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