A 200-g sample of a metal absorbs 3,080 J as it is heated from 20°C to 60°C. What is the identity of the sample?
A. Iron
B. Aluminum
C. Gold
D. copper

Respuesta :

The identity of the sample is copper. The correct option is  D. copper

To determine the identity of the sample, we will determine its specific heat, c.

From the formula

Q = mcΔT

Where Q is the quantity of heat

m is the mass

c is the specific heat of the substance

and ΔT is the change in temperature

From the given information

Q = 3080 J

m = 200 g

ΔT = T₂ - T₁ = 60°C - 20°C = 40°C

Putting the parameters into the formula, we get

3080 = 200 × c × 40

3080 = 8000c

∴ c = 3080 ÷ 8000

c = 0.385 J / g°C

From specific heat table, the substance that has a specific heat of 0.385 J / g°C is Copper.

Hence, the identity of the sample is copper. The correct option is  D. copper

Learn more here: https://brainly.com/question/13439286

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