Answer:
x > 0
Step-by-step explanation:
Given :-
And we need to find the value of x for which the expression is defined . The expression is ,
[tex]:\implies[/tex] √[3x²] ÷ √[4x]
As we can see that x is inside the squareroot. So for defining the expression the value of x should be Greater than 0 . As negative inside the squareroot will give rise to imaginary numbers.
Solution :-
[tex]:\implies[/tex] x > 0
In interval notation :-
[tex]:\implies\bf x \in ( 0 , \infty) [/tex]
Therefore x should be Greater than 0 .
