2. CuCl₂·2H₂O is limiting reactant.
Chemical reaction: 3CuCl₂·2H₂O + 2Al → 3Cu + 2AlCl₃ + 6H₂O. m(Al) = 0,5 g.
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The limiting reagent would be CuCl₂·2H₂O
They are reactants that determine how much of the product is formed in a reaction.
From the balanced equation of the reaction:
3CuCl₂·2H₂O + 2Al → 3Cu + 2AlCl₃ + 6H₂O
Mole ratio of AI to CuCl₂·2H₂O = 2:3
mole of 0.5 g AI = 0.5/28.96
= 0.017 mole
Mole of 3.5 g CuCl₂·2H₂O = 3.5/179.48
= 0.020 mole
Equivalent mole of CuCl₂·2H₂O = 0.017 x 3/2
= 0.026 mlole
Thus, CuCl₂·2H₂O is limited and determines the overall rate of the reaction.
More on limiting reactants can be found here: https://brainly.com/question/14225536