Answer:
860. g CuCl₂
General Formulas and Concepts:
Atomic Structure
- Reading a Periodic Table
- Compounds
- Moles
Stoichiometry
- Using Dimensional Analysis
Explanation:
Step 1: Define
[Given] 6.40 mol CuCl₂
[Solve] g CuCl₂
Step 2: Identify Conversions
[PT] Molar Mass of Cu: 63.55 g/mol
[PT] Molar Mass of Cl: 35.45 g/mol
Molar Mass of CuCl₂: 63.55 + 2(35.45) = 134.45 g/mol
Step 3: Convert
- [DA] Set up: [tex]\displaystyle 6.40 \ mol \ CuCl_2(\frac{134.45 \ g \ CuCl_2}{1 \ mol \ CuCl_2})[/tex]
- [DA] Multiply [Cancel out units]: [tex]\displaystyle 860.48 \ g \ CuCl_2[/tex]
Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
860.48 g CuCl₂ ≈ 860. g CuCl₂
