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A gas is at a pressure of 12 atm, a volume of 23 L, and a temperature of 200 K. If the pressure is raised to 14 atm, and the temperature is increased to 300 K. What is the new volume of the gas? (Show your work, including formula used)

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drpelezo

Answer:

≅ 30 Liters (1 sig. fig. based on Temp values 200K & 200K)

Explanation:

P₁ = 12 atm      =>    P₂ = 14 atm   Increase P  =>  Decrease V  => (12atm/14atm)

V₁ = 23 Liters  =>    V₂ =   ?          

T₁ = 200 K       =>    T₂ = 300 K    Increase T  =>  Increase V  =>  (300K/200K)

V₂ = V₁(P₁/P₂)(T₂/T₁) = 23L(12atm/14atm)(300K/200K) = 29.57143 L (Calc. Ans.)

≅ 30 Liters (1 sig. fig. based on Temp values 200K & 200K)

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