Given:
The equation is:
[tex]192=6000\left(0.02\left(\dfrac{8}{5}-4y\right)+0.08y\right)[/tex]
To find:
The value of y.
Solution:
We have,
[tex]192=6000\left(0.02\left(\dfrac{8}{5}-4y\right)+0.08y\right)[/tex]
On simplification, we get
[tex]192=6000\left(0.02\times 1.6-0.02\times 4y+0.08y\right)[/tex]
[tex]192=6000\left(0.032-0.08y+0.08y\right)[/tex]
[tex]192=6000\left(0.032\right)[/tex]
[tex]192=192[/tex]
Since LHS=RHS and the equation is free from the variable y, therefore the given equation is true for all real values of y.
Hence, all real values of y are solutions.
