Answer:
[tex]:\implies \boxed{\red{\sf m \in (-1,-\infty)}}[/tex]
Step-by-step explanation:
Given :-
- A linear inequality 4m +6<2
We need to find the solution set for the given inequality . So , on solving it , we have ,
[tex]:\implies[/tex] 4m + 6 < 2
[tex]:\implies[/tex] 4m < 2 - 6
[tex]:\implies[/tex] 4m < -4
[tex]:\implies[/tex] m < -4/4
[tex]:\implies[/tex] m < -1
Hence m can have all values less than -1. Therefore the final answer is ,
[tex]:\implies \boxed{\red{\sf m \in (-1,-\infty)}}[/tex]
Hence m can have all values less than-1.
