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Please (You can put answer only) Find the distance between the two points rounding to the nearest tenth (if necessary).
(4, -8) and (2, -4)

Respuesta :

VirαtKσhli

Answer:

12.16 u

Step-by-step explanation:

Given :-

  • Two points (4,-8) and (2,-4) is given to us.

And we need to find out the distance between the two points . So , here we can use the distance formula to find out the distance. As,

[tex]:\implies[/tex] D = √{(x2-x1)² + (y2-y1)²}

[tex]:\implies[/tex] D =√[ (4-2)² +(8+4)²]

[tex]:\implies[/tex] D =√[ 2² +12²]

[tex]:\implies[/tex] D =√[ 4 +144]

[tex]:\implies[/tex] D = 12.16

Hence the distance between the two points is 12.16 units .
(The answer is 4.5) Distance between formula is √(xB-xA) ²+ (yB-yA) ² now you plug in your points (4, -8) (2, -4)
√(2-4) ² +(-4 - -8) ² which would then get you √(-2) ² + 4 ² then √4+16 to √20 which would be 4.47 which you round up 4.5. (First set of points(4, -8) 4=xA,-8=yA) (Second set of points=(2, -4) 2=xB, -4=yB) √ is a square root, ² is a second power it means whatever the number associated with it is getting multiplied by itself or two times so example 5 ² is 5x5 or 7 ² is 7x7 or 9 ² is 9x9.
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