Respuesta :
Question:-
As a block of ice melts, its weight changes from 1 3/4 lb to 1/4 lb. This change takes 1/4 h. The ice melts at a constant rate. At what rate does the weight of the ice change?
Answer:-
You should have these values backwards like:-
=> 1/34 lb is less than 1/4 lb.
Next:-
We're gonna find a specific common denominator,
Then we get: (17/68 - 2/68)/(1/4) = 60/68 = 15/17 lb/hour
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[tex]\huge{ \mathfrak{ \underline{ Answer}}} \: \: ✓ [/tex]
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Change in weight :
- [tex]1 \dfrac{3}{4} - \dfrac{1}{4} [/tex]
- [tex] \dfrac{7}{4} - \dfrac{1}{4} [/tex]
- [tex] \dfrac{6}{4} lb[/tex]
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Time taken to melt :
- [tex]\dfrac{1}{4} \: hr[/tex]
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Rate of change in weight of ice :
- [tex] \mathrm{ \dfrac{change \: \: in \: \: weight}{time \: taken} }[/tex]
- [tex] \dfrac{6}{4} \div \dfrac{1}{4} [/tex]
- [tex] \dfrac{6}{4} \times 4[/tex]
- [tex]6[/tex]
The rate of change in weight of Ice is 6 lbs per hour ( 6 lb / h )
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[tex]\mathrm{ \#TeeNForeveR}[/tex]
