Answer:
[tex]\boxed {\boxed {\sf d\approx 4.2}}[/tex]
Step-by-step explanation:
The formula for distance is:
[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2[/tex]
Where (x₁, y) and (x₂, y₂) are the points.
We are given (-6, 6) and (-3, 3). If we match the value and its corresponding variable, we see that:
- x₁= -6
- y₁ = 6
- x₂ = -3
- y₂ = 3
Substitute the values into the formula.
[tex]d= \sqrt{ (-3 - -6)^2+(3-6)^2[/tex]
Solve inside the parentheses.
- -3 --6 = -3+6 = 3
- 3-6 = -3
[tex]d= \sqrt{(3)^2+ (-3)^2[/tex]
Solve the exponents.
- (3)²= 3*3= 9
- (-3)²= -3*-3 =9
[tex]d= \sqrt{9+9[/tex]
Add.
[tex]d= \sqrt18[/tex]
[tex]d= 4.24264069[/tex]
Round to the nearest tenth. The 4 in the hundredth place tells us to leave the 2 in the tenth place.
[tex]d \approx 4.2[/tex]
The distance between the two points is apprximately 4.2
