alexandraguiler
contestada

A ball is kicked 4 feet above the ground with an initial vertical velocity of 51 feet per second. The function h(t)=−16t²+51t+4 represents the height h (in feet) of the ball after t seconds. Using a graph, after how many seconds is the ball 28 feet above the ground? Round your answers to the nearest tenth.

Respuesta :

Answer:

0.6 seconds to 2.6 seconds

Step-by-step explanation:

From the graph the ball reaches 28 feet after 0.574 seconds

and doesn't fall below that until 2.614 seconds

0.574 rounded is 0.6 seconds

2.614 rounded is 2.6 seconds

Ver imagen Аноним

Answer:

0.57 seconds (see graph)

Step-by-step explanation:

h(t) = -16t² + 51t + 4

h(t) = 28

28 = -16t² + 51t + 4

0 = -16t² + 51t - 24

t1 = 2.613573055

t2 = 0.5739269455 (pick this answer)

The ball will be 28 feet above the ground after 0.57 seconds

Ver imagen goddessboi
ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE

Otras preguntas