Answer:
4x^11 [tex]\sqrt{5}[/tex]
Step-by-step explanation:
You can simplify the 20 inside of the radical by finding its prime factors. 20 has 3 prime factors: 5, 2, and 2. Since the 2 occurs twice, we can cancel out those 2s in the 20 itself and put a singular 2 outside of the radical. It is essentially turning [tex]\sqrt{20}[/tex] into 2[tex]\sqrt{5}[/tex]. Since we now have simplified that 20, the entire equation is now 4x[tex]\sqrt{5x^2^0}[/tex]. We can root x^20 to get x^10, and [tex]\sqrt{5}[/tex] stays that way. The entire equation is now 4x[tex]\sqrt{5}[/tex]x^10, which can be simplified to [tex]4x^1^1\sqrt{5}[/tex].
