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Points A and B lie on a circle with radius 1, and arc AB ⌢ has a length of [tex]\frac{\pi }{3}[/tex]. What fraction of the circumference of the circle is the length of arc AB ⌢?

Respuesta :

msm555

Answer:

Solution given:

arc AB :angle=[tex]\frac{\pi }{3}[/tex]=60

radius[r]=1

Now

we have

Circumference the circle is the length of arc AB ⌢:[tex]\frac{arc AB }{360}2\pi*r[/tex]

:

[tex] \frac{180}{3} \div 360 \times 2\pi \: \times 1[/tex]

=⅓π or 1.047units

Note:

For angle π=180

For length π=[tex]\frac{22 }{7}[/tex].

L

  • Ø/360×2πr

π/3=60°

  • L=60/360×2π(1)
  • L=1/6×2π
  • L=π/3
  • L=1.047units
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