The square root of the quadratic equation [tex](x^2 -6x+ 9)[/tex] if x<-3 would be equal to (x-3).
What is a quadratic equation?
A quadratic equation is the second-order degree algebraic expression in a variable. the standard form of this expression is ax² + bx + c = 0 where a. b are coefficients and x is the variable and c is a constant.
The given quadratic equation is
[tex](x^2 -6x+ 9)[/tex]
We have to find the square root of the quadratic equation
[tex]\sqrt{(x^2 -6x+ 9)} \\\\\sqrt{(x^2 -3x-3x+ 9)} \\\\\sqrt{x(x-3)-3 (x-3)} \\\\\sqrt{(x-3) (x-3)} \\\\\sqrt{(x-3)^2} \\\\(x-3)[/tex]
Thus, the square root of the quadratic equation [tex](x^2 -6x+ 9)[/tex] if x<-3 would be equal to (x-3).
Learn more about quadratic equations;
brainly.com/question/13197897
#SPJ2
