If [tex]\sum _{n=1}^{\infty }\:\frac{6}{3^n}=3[/tex] then, The truncation error for S4 is equal to 0.037.
We have given that,
[tex]\sum _{n=1}^{\infty }\:\frac{6}{3^n}=3[/tex]
We have to determine the value of S_4
Here plug the value n=4.
A series is the sum of a sequence. In other words, a series is just the addition of all the terms in a sequence.
Therefore we get,
[tex]\sum _{n=1}^{\infty }\:\frac{6}{3^4}=3[/tex]
Therefore the value of S_4=0.037
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