Answer:
8 possible seats
Step-by-step explanation:
Given
[tex]n = 8[/tex] ---booths
[tex]r = 1[/tex] --- hostess
Required
Number of possible seats (order is important)
If order is important, then we solve using permutation
i.e.
[tex]^nP_r = \frac{n!}{(n - r)!}[/tex]
So, we have:
[tex]^{8}P_1 = \frac{8!}{(8 - 1)!}[/tex]
This gives:
[tex]^{8}P_1 = \frac{8!}{7!}[/tex]
Expand
[tex]^{8}P_1 = \frac{8*7!}{7!}[/tex]
[tex]^{8}P_1 = 8[/tex]
