Ms. Parker determined that the mean test score in her first-period class
was 81 with a standard deviation of 7.06. The mean test score in her
second-period class was 88 with a standard deviation of 8.24. Which
conclusion can be made about her students' test scores?
A Period 2 had scores that were less spread out around the mean than
Period 1.
B. Period 1 had scores that were less spread out around the mean than
Period 2.
C. Period 2 had scores that were less spread out around the median than
Period 1.
D
Period 1 had scores that were less spread out around the median than
Period 2.

Respuesta :

Answer:

B. Period 1 had scores that were less spread out around the mean than

Period 2

Step-by-step explanation:

Because the standard deviation of Period 2's scores is greater than that of Period 1's, the test scores for Period 2 are going to be more spread out than Period 1's test scores. B is the most logical choice in this case.

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