Answer: [tex]\frac{1}{\sqrt{5}}[/tex] or [tex]\frac{\sqrt{5}}{5}[/tex]
Step-by-step explanation:
The sine of an angle is equal to the opposite of leg of the triangle over the hypotenuse. Since the side opposite angle A is 5, and the hypotenuse is [tex]5\sqrt{5}[/tex], then sinA = [tex]\frac{5}{5\sqrt{5} }[/tex], simplified to [tex]\frac{1}{\sqrt{5}}[/tex] and rewritten as [tex]\frac{\sqrt{5}}{5}[/tex]
