Answer: [tex]0.65\ J/g.^{\circ}C[/tex]
Explanation:
Given
Mass of iron piece is [tex]m=17.98\ g[/tex]
Heat absorbed [tex]Q=2056.5\ J[/tex]
Temperature changes from [tex]25^{\circ}C\ to\ 200^{\circ}C[/tex] i.e.
[tex]\Delta T=200-25=175^{\circ}C[/tex]
Heat absorbed is given by [tex]Q=mc\Delta T\quad [c=\text{specific heat of material}][/tex]
Insert the values
[tex]\Rightarrow 2056.5=17.98\times c\times 175\\\\\Rightarrow c=\dfrac{2056.5}{3146.5}\\\\\Rightarrow c=0.65\ J/g.^{\circ}C[/tex]
Thus, the specific heat of iron is [tex]0.65\ J/g.^{\circ}C[/tex]
