Answer:
Explanation:
4NH₃ + 7O₂ --> 4NO + 6H₂O
4 moles 7 moles
58.3 g of NH₃ = 58.3 / 17 = 3.43 moles
126 g of O₂ = 126 / 32 = 3.94 moles
4 moles NH₃ requires 7 moles of O₂
3.43 moles NH₃ requires 6 moles O₂
Available O₂ is only 3 94 moles , so O₂ is in short supply .
Hence O₂ is the limiting reagent .
