Answer:
Solution given;
for sphere
radius [r]:12inches
another
radius [R]:9inches
Now
difference in volume of sphere:
volume of sphere of having radius [r-R]
=[tex] \frac{4}{3} πr³[/tex]-[tex] \frac{4}{3} πR³[/tex]
=[tex] \frac{4}{3} π[/tex](12³-9³)
= 1332π cubic inches
The volume of the larger sphere is ___1332__π cubic inches greater than the volume of the smaller sphere.
