Answer:
5, 15, 45 and 135
Step-by-step explanation:
Given the recursive function;
an = 3a(n-1)
If a1 = 5
a2 = 3a1
a2 = 3(5)
a2 = 15
For a3;
a3 = 3a2
a3 = 3(15)
a3 = 45
For a4;
a4 = 3a3
a4 = 3(45)
a4 = 135
Hence the first four terms are 5, 15, 45 and 135
