Answer:
[tex]Area = 24\ in^2[/tex]
Step-by-step explanation:
Given
Let
[tex]a, b \to[/tex] opposite sides of each trapezoid
[tex]h \to[/tex] height
[tex]a = 2; \ \ \ b = 4 \ \ \ \ h = 2[/tex]
See attachment for trapezoids
Required
The combined area of the 4
First, we calculate the area of 1
[tex]Area = \frac{1}{2}(a + b) * h[/tex]
So:
[tex]A_1 = \frac{1}{2}(2 + 4) * 2[/tex]
[tex]A_1 = \frac{1}{2}*6 * 2[/tex]
Using a calculator
[tex]A_1 = 6[/tex]
The combined area is:
[tex]Area =n * A_1[/tex]
Where
[tex]n = 4[/tex] --- 4 blades
So:
[tex]Area = 4 * 6[/tex]
[tex]Area = 24\ in^2[/tex]
