Answer:
The right solution is "0.15%".
Step-by-step explanation:
The given values are:
Mean,
[tex]\bar{x}=54.82[/tex] $
Standard deviation,
[tex]s = 8.95[/tex] $
[tex]P(X>81.67)[/tex]
Now,
= [tex]P(z>\frac{81.67-\bar{x}}{s} )[/tex]
On substituting the values, we get
= [tex]P(z>\frac{81.67-54.82}{8.95} )[/tex]
= [tex]P(z>\frac{26.85}{8.95})[/tex]
= [tex]P(z>3)[/tex]
By using the table, we get
= [tex]0.0015[/tex]
= [tex]0.15[/tex]%
