Please help me solve this answer. Just give the correct answer.

Answer:
2. B. 30 sq yd
Step-by-step explanation:
[tex]area = area \: of \: triangle \: + \: area \: of \: parallelogram \\ but \: area \: of \: parallelogram = area \: of \: rectangle - area \: of \: two \: small \: triangles \\ = (4 \times 8) - 2( \frac{1}{2} \times 3 \times 4) \\ = 32- 12 \\ = 20 \: sq \: yards \\ area = (\frac{1}{2} \times 5 \times 4) + 8 \\ = 10 + 20 \\ = 30 \: sq \: yards[/tex]
Answer:
The area of shaded figure is 30 sq yards .
Step-by-step explanation:
In the graph the figure is consist of :
To calculate the area of shaded figure we need to find the area of triangle and parallelogram and combine them to get the area of shaded figure.
Finding the area of triangle:-
Area of triangle = ½ × Base × Height
Area of triangle = ½ × 5 × 4
Area of triangle = ½ × 20 yard²
Hence, the area of triangle is 10 sq yards.
Finding the area of parallelogram :
Here, to calculate the area subtract the area of two small circle from the area of rectangle .
Area of parallelogram = l × b - 2 (( b × h )½)
Area of parallelogram = 4 × 8 - 2 ( 3 × 4 × ½)
Area of parallelogram = 32 - 12.
Area of parallelogram = 20 sq yards.
Hence, Area of parallelogram = 20 sq yards.
Area of figure = Area of parallelogram + Area of triangle.
Area of figure = 20 sq yards + 10 sq yards.
Area of figure = 30 sq yards .
Hence,
The area of shaded figure is 30 sq yards .