1.Distribute
-30=5(x+1). x
[tex]-30=5x^{2}+5x[/tex]
2. Move terms to the left side
[tex]-30=5x^{2} +5x[/tex]
[tex]-30-(5x^{2} +5x)=0[/tex]
3. Rearrange terms
[tex]-30-5x^{2} -5x=0[/tex]
[tex]-5x^{2} -5x-30=0[/tex]
Hope this helps! Sorry if I'm wrong
[tex]\huge\text{Hey there!}[/tex]
[tex]\large\text{ORIGINAL EQUATION}\downarrow[/tex]
[tex]\large\textsf{ -30 = 5(x + 1)}[/tex]
[tex]\large\text{TURN the EQUATION}[/tex]
[tex]\large\textsf{5(x + 1) = -30}[/tex]
[tex]\large\text{DISTRIBUTE \textsf{5} WITHIN the PARENTHESES}[/tex]
[tex]\large\textsf{5(x) + 5(1) = -30}[/tex]
[tex]\large\textsf{5(x) = \bf 5x}\\\large\textsf{5(1) = 5}[/tex]
[tex]\rightarrow\large\textsf{5x + 5 = -30}[/tex]
[tex]\large\text{NEW EQUATION: \textsf{5x + 5 = -30}}[/tex]
[tex]\large\text{SUBTRACT \textsf{5} to BOTH SIDES}[/tex]
[tex]\large\textsf{5x + 5 - 5 = -30 - 5}[/tex]
[tex]\large\text{CANCEL out: \textsf{5 - 5} because that gives you \textsf{0}}[/tex]
[tex]\large\text{KEEP: \textsf{-30 - 5} because that helps you solve for your \textsf{x-value}}[/tex]
[tex]\large\textsf{-30 - 5 = \bf -35}[/tex]
[tex]\large\text{NEW EQUATION: \textsf{5x = -35}}[/tex]
[tex]\large\text{DIVIDE \textsf{5} to BOTH SIDES}[/tex]
[tex]\mathsf{\dfrac{5x}{5}= \dfrac{-35}{5}}[/tex]
[tex]\large\text{CANCEL out: }\mathsf{\dfrac{5x}{5}}\large\text{ because that gives you the value of \textsf{1}}[/tex]
[tex]\large\text{KEEP: }\mathsf{\dfrac{-35}{5}}\large\text{ gives you the \textsf{x-value}}[/tex]
[tex]\large\textsf{x = }\mathsf{\dfrac{-35}{5}}[/tex]
[tex]\large\text{SIMPLIFY ABOVE \& YOU HAVE YOUR x-value}[/tex]
[tex]\boxed{\boxed{\large\textsf{ANSWER: \huge \bf x = -7}}}\huge\checkmark[/tex]
[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
