Answer:
It's b. %99.7
Step-by-step explanation:
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The widest confidence interval that will be produced the 99.7%, given a sample proportion of 0.4.
If the sample size is given to be n < 30, then for finding the confidence interval for the mean of the population from this small sample, we use the t-statistic.
Let the sample mean given as [tex]\overline{x}[/tex] and
The sample standard deviation s, and
The sample size = n, and
The level of significance = [tex]\alpha[/tex]
Then, we get the confidence interval in between the limits
[tex]\overline{x} \pm t_{\alpha/2}\times \dfrac{s}{\sqrt{n}}[/tex]
where [tex]t_{\alpha/2}[/tex] is the critical value of 't' that can be found online or from tabulated values of critical value for a specific level of significance and degree of freedom n - 1.
In statistics, a confidence interval is a range to estimate for unknown terms. The most common level is the 95% confidence interval.
So, the widest confidence interval that will be produced the 99.7%, given a sample proportion of 0.4.
Learn more about confidence intervals;
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