Answer:
Height of the arch at distances of 10, 30, and 50 feet from the center is as follow:
Put x = 10 we get
the value of y = 0.695
Put x = 30
the vale of y = 6.26
Put x = 50
the value of y = 17.37
Step-by-step explanation:
The prabolic arch for bridge has span of 120 feet and height f 25 feet. The rectangular corordinate system is
such as
height = h = 25
Distance = x
(x-h) = -4a(y-k)
x² = -4ay
60 = -4a(-25) and
where the value of a =36
therefor the parabolic arch is
x = -144y
For distance of 10 , 20 and 30 let take the feet from center then we have
put x = 10 we get
10² = -144 y
100 / 144 = y
the value of y = 0.695
Put x = 30
30² = -144y
30/144 = y
the vale of y = 6.26
Put x = 50
50² = -144 y
50/144 = y
the value of y = 17.37
