Answer: The average kinetic energy of water at [tex]25^{o}C[/tex] is [tex]1.233 \times 10^{-26} J[/tex].
Explanation:
Given: Temperature = [tex]25^{o}C = (25 + 273) K = 298 K[/tex]
Kinetic energy is the energy acquired by the molecules of a substance due to its motion.
Formula to calculate average kinetic energy is as follows.
[tex]K.E = \frac{3}{2}kT[/tex]
where,
T = temperature
k = Boltzmann constant = [tex]1.38 \times 10^{-23} J/K[/tex]
Substitute the value into above formula as follows.
[tex]K.E = \frac{3}{2}kT\\= \frac{3}{2} \times 1.38 \times 10^{-23} J/K \times 298 K \\= 1.233 \times 10^{-26} J[/tex]
Thus, we can conclude that the average kinetic energy of water at [tex]25^{o}C[/tex] is [tex]1.233 \times 10^{-26} J[/tex].
