A current of 2.50 amps is passed through an electrolytic cell containing a solution of M(NO3)2, where M represents an unidentified metal. The only reaction that occurs at the cathode is the deposition of the unknown metal. After 2.00 hours, 5.93 g of the metal has been deposited.

Required:
Determine the chemical symbol of the metal.

Respuesta :

Answer:

The chemical symbol will be "[tex]_{29}^{63.5}\textrm{Cu}[/tex]".

Explanation:

The given values are:

Current,

I = 2.50 amps

Time,

t = 2 hr

or,

 = 7200 sec

Metal deposited,

W = 5.93 gm

As we know,

⇒  [tex]W=Z\times i\times t[/tex]

or,

⇒  [tex]Z=\frac{W}{i\times t}[/tex]

On putting the given values, we get

⇒      [tex]=\frac{5.93}{2.5\times 7200}[/tex]

⇒      [tex]=3.2945\times 10^{-4}[/tex]

hence,

⇒ [tex]Atomic \ mass=Z\times electrons\times 96500[/tex]

⇒                       [tex]=3.2945\times 10^{-4}\times 2\times 96500[/tex]

⇒                       [tex]=63.5[/tex]

Thus the above is the right answer.

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