Respuesta :
Answer:
[tex]x+2y = 5\\x = 5 -2y\\\\Substitute \ x \ in \ second \ equation \\\\3(5-2y) +5y = 14\\15 -6y +5y = 14\\-y = 14 -15\\-y = -1\\y = 1\\Substitute \ y = 1 \ in \ x = 5 -2y:\\ x = 5 -(2\cdot 1) = 5-2=3\\[/tex]
Option (3, 1)
Answer:
The solution is (3, 1)
Step-by-step explanation:
Use the method "elimination by addition and subtraction." Multiply all terms of the first equation by -3, obtaining
-3x - 6y = -15
and combine this result with the second equation:
-3x - 6y = -15
3x + 5y = 14
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-y = -1, or y = 1.
Substituting this result, y = 1, into the first equation yields
x + 2(1) = 5, or x + 2 = 5, or x = 3.
The solution is (3, 1)