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please help, i'll give brainliest if correct :)
select the correct answer from each drop-down menu
the vertex of a parabola is (-1.5, -12.5), and its y-intercept is (0,-8).
the x-intercepts of the parabola are ! a) (-2,0) ! b) (-4,0) ! c) (2,0) ! d) (4,0) !
and ! a) (-1,0) ! b) (2,0) ! c) (1,0) ! d) (2,0)
please answer asap!! thank you ~

Respuesta :

Crocodile27

Answer:

Step-by-step explanation:

The equation should be:

[tex]y=a(x+1.5)^2-12.5\\ because\\ y = a(x+h)^2 +k \\plug x=0,y=8\\-8 = a(0+1.5)^2 -12.5[/tex]

Therefore we simplify this and

[tex]4.5= a * 2.25\\a = 2[/tex]

Therefore,

[tex]y = 2(x+1.5)^2 -12.5\\y = 2(x^2 +3x +2.25) - 2*6.25\\y= 2(x^2 +3x +2.25 - 6.25)\\y= 2(x^2 +3x -4)\\[/tex]

Then you use the simplifying rule for quadratic equations: I'll link something below

y = 2 (x -4)(x+1)

so the x intercept is when y = 0, and y = 0 when x-4 = 0 or x+1 =0,

therefore x=4, x=-1

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