The sample space of picking a 2
character password using the letters Y, P, GR,
B, O, where double letters are not allowed is
shown. Your teacher asks the class to find the
probability of choosing a password with
one Y and one P. Carlos incorrectly says that
the probability is 15. Find the correct probability
then decide which error Carlos might have
made

The sample space of picking a 2 character password using the letters Y P GR B O where double letters are not allowed is shown Your teacher asks the class to fin class=

Respuesta :

Answer:

[tex]Pr = \frac{1}{15}[/tex]

Step-by-step explanation:

Given

See attachment for sample space

Required

[tex]P(1\ Y\ and\ 1\ P)[/tex]

From the attached sample space, we have:

[tex]n(S) =30[/tex] ---- total outcomes

[tex]n(PY) = 2[/tex] --- outcomes with 1 Y and 1 P = 2 i.e. (P,Y) and (Y,P)

So, the required probability is:

[tex]Pr = \frac{n(PY)}{n(S)}[/tex]

[tex]Pr = \frac{2}{30}[/tex]

[tex]Pr = \frac{1}{15}[/tex]

The error is that; Carlos omitted the numerator

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