Answer:
Zn (s) + HCl (aq) → ZnCl₂ (aq) + H₂ (g) ↑
Explanation:
Let's define the reactants:
Zn (s)
HCl (aq)
One of the product is: H₂ (g)
This reaction can also produce ZnCl₂ (s)
Let's make the reaction:
Zn (s) + HCl (aq) → ZnCl₂ (aq) + H₂ (g) ↑
Notice that the the hydrogen gas is released from the tube, that's why the up arrow.
This is a redox reaction because the Zn and H chage their oxidation states.
Zn ⇄ Zn²⁺ + 2e⁻ Oxidation (it released two electrons)
Oxidation state is increased
2H⁺ + 2e⁻ → H₂ Reduction (It gained two electrons)
Oxidation state is decreased
The oxidation state of elements at ground state is 0
