The capacitance of the capacitor if the dielectric constant of the paper is 3.7 : 18 nF
Given data :
Thickness of aluminium capacitor = 0.022 mm
Number of sheets = 500
Thickness of ream = 5.5 cm = 0.055 m
measurement of sheets = 0.216 m by 0.279 m
dielectric constant ( k ) = 3.7
Determine the capacitance of the capacitor
we will apply the capacitance formula below
C = Kε₀A / d
= 3.7 * 8.85*10⁻¹² * 0.216 *0.279 / ( 0.055 / 500 )
= 1.8 * 10⁻⁸F ≈ 18nF
Hence we can conclude that The capacitance of the capacitor if the dielectric constant of the paper is 3.7 : 18 nF
Learn more about Capacitance : https://brainly.com/question/13578522
