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How many moles are there in a 2,500 cm 'sample of oxygen at a temperature of 24 °C and a pressure
of 125 kPa?

Respuesta :

Explanation:

using the formula pv=nRt

where p= pressure =125

v= volume =2500= 25.oom3 to meter

n = mumber of moles =?

T= temperature = 24 =24+273=297k

[tex]molarity \: \: constant \: = 8.3j mol {}^{- 1} {k}^{- 1} [/tex]

which is given as R

so inputting the values we have

125×25=n×8.3×297

3125=2465.1n

dividing all with the coefficient of n we have

[tex] \frac{3125}{2465.1} = 2465.1 \24651[/tex]

1.27= n

therefore no of moles =1.27

The no of moles are there in a 2,500 cm sample of oxygen at a temperature of 24 °C and a pressure of 125 kPa will be 1.27.

What is ideal gas equation?

It is the relationship between the pressure,volume and the temperature. Ideal gas equation is found as;

pv=nRt

Given data is;

p(pressure) =125

v(volume) =2500 cm = 25.m³

n(number of moles) =?

T(temperature) = 24°C =24+273=297k

From Ideal gas equation ;

pv=nRt

125×25=n×8.3×297

3125=2465.1 n

n=1.27

Hence,the no of moles will be 1.27.

To know more about the ideal gas equation refer to the link;

https://brainly.com/question/4147359

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