Answer:
The mean of A and C is equal to 10.
Step-by-step explanation:
We know that,
[tex]\text{Mean}=\dfrac{\text{Sum of observations}}{\text{Total no of obervations}}[/tex]
The mean of A and B is 20,
[tex]A+B=20\\\\A+B=40\ \ .........(1)[/tex]
The mean of B and C is 24,
[tex]B+C=24\times 2\\\\B+C=48\ \ .........(2)[/tex]
The mean of A,B and C is 18,
[tex]A+B+C=18\times 3\\\\A+B+C=54\ .....(3)[/tex]
Put the value of A+B from (1) in (3),
C = 14
Put the value of B+C from (2) in (3)
A = 6
Mean of A and C is :
[tex]M=\dfrac{A+C}{2}\\\\M=\dfrac{14+6}{2}\\\\M=10[/tex]
So, the mean of A and C is equal to 10.
