Answer:
ΔV = 78 V
Explanation:
The potential at a point due to a point charge is given as:
[tex]V = \frac{kq}{r}[/tex]
where,
V = Potential at the point
k = Colomb's Constant = 9 x 10⁹ Nm²/C²
q = charge = 3.25 x 10⁻⁹ C
r = distance
AT POINT A:
[tex]V_A = \frac{(9\ x\ 10^9\ Nm^2/C^2)(3.25\ x\ 10^{-9}\ C)}{0.15\ m} \\\\V_A = 195\ V[/tex]
AT POINT B:
[tex]V_B = \frac{(9\ x\ 10^9\ Nm^2/C^2)(3.25\ x\ 10^{-9}\ C)}{0.25\ m} \\\\V_B = 117\ V[/tex]
Now, the potential difference will be:
[tex]\Delta V = V_A-V_B = 195\ V - 117\ V[/tex]
ΔV = 78 V
