Answer:
2.7x10⁻⁷mol/L
Explanation:
Based on the equilbrium:
PbCO₃(s) ⇄ Pb²⁺(aq) + CO₃²⁻(aq)
The solubility product, Ksp, is defined as:
Ksp = 7.4x10⁻¹⁴ = [Pb²⁺] [CO₃²⁻]
Now, solubility is defined as the amount of PbCO₃ that is dissolved, that is the concentration of the ions. Thus:
Solubility = S = [Pb²⁺] = [CO₃²⁻]
Replacing:
7.4x10⁻¹⁴ = [S] [S]
7.4x10⁻¹⁴ = [S]²
S = 2.7x10⁻⁷mol/L
