What is Limit of g (x) as x approaches 1, if it exists?
0
7,000,000
700,000,000
DNE

Answer:
7,000,000
Step-by-step explanation:
Limit of a function:
The limit of a function is finding looking at it's lateral limits.
If the lateral limits are equal:
The limit exists.
[tex]\lim_{x \rightarrow a} f(x) = \lim_{x \rightarrow a^{+}} f(x) = \lim_{x \rightarrow a^{-}} f(x)[/tex]
If lateral limits are different:
That is:
[tex]\lim_{x \rightarrow a^{+}} f(x) \neq \lim_{x \rightarrow a^{-}} f(x)[/tex], then the limit does not exist.
In this question:
To the left of 1, that is, 0.9999....
[tex]\lim_{x \rightarrow 1^{-}} g(x) = 7,000,000[/tex]
To the right of 1, that is, 1.0001...
[tex]\lim_{x \rightarrow 1^{+}} g(x) = 7,000,000[/tex]
Since the both limits are the same, the limits exists and it's value is of 7,000,000.
Answer:
D
Step-by-step explanation:
It shows it in the quwestions image