Answer:
[tex]P(-2 \le x \le 2) =0.60[/tex]
Step-by-step explanation:
Given
[tex]\begin{array}{ccccccc}x & {-5} & {-3} & {-2} & {0} & {2} & {3} \ \\ P(x) & {0.17} & {0.13} & {0.33} & {0.16} & {0.11} & {0.10} \ \end{array}[/tex]
Required
[tex]P(-2 \le x \le 2)[/tex]
From the distribution, the above is equivalent to:
[tex]P(-2 \le x \le 2) =P(x = -2) +P(x = 0)+P(x = 2)[/tex]
We have:
[tex]P(x = -2) = 0.33[/tex]
[tex]P(x = 0)=0.16[/tex]
[tex]P(x = 2) = 0.11[/tex]
So:
[tex]P(-2 \le x \le 2) =P(x = -2) +P(x = 0)+P(x = 2)[/tex]
[tex]P(-2 \le x \le 2) = 0.33 + 0.16 +0.11[/tex]
[tex]P(-2 \le x \le 2) =0.60[/tex]
