Answer:
Mass of methane required in gram = 226.35 gram (Approx.)
Explanation:
Given:
Heat energy used = 12,567 kJ
Missing data;
Δcombustion = 891 kJ/mol
Find:
Mass of methane required in gram
Computation:
Number of mol methane burned = Heat energy used / Δcombustion
Number of mol methane burned = 12,571 / 891
Number of mol methane burned = 14.1088 mol
1 mol of methane in gram = 16.043 grams
So,
Mass of methane required in gram = Number of mol methane burned x 1 mol of methane in gram
Mass of methane required in gram = 14.1088 x 16.043
Mass of methane required in gram = 226.3474
Mass of methane required in gram = 226.35 gram (Approx.)
