Answer:
4.7 × 10⁴ J
Explanation:
Step 1: Given data
- Initial temperature: 25 °C
- Final temperature: 100 °C
- Specific heat capacity of water (c): 4.184 J/g.°C
Step 2: Calculate the temperature change (ΔT)
ΔT = 100 °C - 25 °C = 75 °C
Step 3: Calculate the heat required (Q) to raise the temperature of the water
We will use the following expression.
Q = c × m × ΔT
Q = 4.184 J/g.°C × 150 g × 75 °C = 4.7 × 10⁴ J
