If 3 balls are drawn at random from a bag containing 3 red and 4 blue balls,
what is the expected number of red balls in the sample?

Respuesta :

Answer:

The expected number of red balls in the sample is 1.2857.

Step-by-step explanation:

The balls are chosen without replacement from the sample, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The expected value of the hypergeometric distribution is:

[tex]E(X) = \frac{nk}{N}[/tex]

3 red balls in the sample:

This means that [tex]k = 3[/tex]

3 balls are drawn:

This means that [tex]n = 3[/tex]

Total of 3 + 4 = 7 balls:

This means that [tex]N = 7[/tex]

What is the expected number of red balls in the sample?

[tex]E(X) = \frac{nk}{N} = \frac{3*3}{7} = 1.2857[/tex]

The expected number of red balls in the sample is 1.2857.

ACCESS MORE
ACCESS MORE
ACCESS MORE
ACCESS MORE