Answer:
The equation for this stretch of roadway in point-slope form is [tex]y - 2225 = 0.04x[/tex]
Step-by-step explanation:
Equation in point-slope form:
The equation of a line in point-slope form is given by:
[tex]y - y_0 = m(x - x_0)[/tex]
In which [tex](x_0,y_0)[/tex] is the point and m is the slope.
A stretch of highway has a 4% uphill grade. This means that the road rises 1 foot for every 25 feet of horizontal distance.
This means that [tex]m = 0.04[/tex]
The beginning of the highway (x = 0) has an elevation of 2,225 feet.
This means that [tex](x_0,y_0) = (0,2255)[/tex]. So
[tex]y - y_0 = m(x - x_0)[/tex]
[tex]y - 2225 = 0.04(x - 0)[/tex]
[tex]y - 2225 = 0.04x[/tex]
The equation for this stretch of roadway in point-slope form is [tex]y - 2225 = 0.04x[/tex]
