Answer:
The slope of line CB is "[tex]-\frac{3}{2}[/tex]".
Explanation:
According to the question,
The two co-ordinates are:
[tex]A(3, 2)=(x_1, y_1)[/tex]
[tex]B(6, 4)=(x_2,y_2)[/tex]
Now,
The slope of line AB will be:
= [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]
= [tex]\frac{4-2}{6-3}[/tex]
= [tex]\frac{2}{3}[/tex]
Now,
According to the perpendicular identity,
⇒ [tex]m_{BC}\times m_{AB}=-1[/tex]
or,
⇒ [tex]m_{BC}=-\frac{1}{m_{AB}}[/tex]
⇒ [tex]=-\frac{1}{\frac{2}{3} }[/tex]
⇒ [tex]=-\frac{3}{2}[/tex]
