The horizontal asymptote of the function f(x) = (x - 2)/(x - 3)²is;
A: y = 0
We are given the function;
f(x) = (x - 2)/(x - 3)²
Expanding the denominator gives us;
f(x) = (x - 2)/(x² - 6x + 9)
The rules for a horizontal asymptote are;
In our given expression, we can see that the degree of the denominator polynomial is greater than that of the numerator and as such the horizontal asymptote is y = 0.
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