Answer:
Yes, the marketing manager's claim is true.
Step-by-step explanation:
p = 0.61
Phat = 545 /826 = 0.66
H0 : p = 0.61
H1 : p ≠ 0.61
The test statistic :
(Phat - p) / √pq/n
q = 1 -p = 1 - 0.61 = 0.39
(0.66 -0.61) / √(0.61*0.39)/826
0.05 / 0.0169709
Test statistic = 2.95
Using the p-value from Zscore calculator:
Pvalue at 2.95, two tailed ;
Pvalue = 0.0032
Reject H0; if Pvalue < α
Since, Pvalue < α ; Then, the marketing manager's claim is true
