Answer:
[tex]F(k)= \frac{9}{5}(k - 273.15) + 32[/tex]
Step-by-step explanation:
Given
[tex]F(c)= \frac{9}{5}c + 32[/tex]
[tex]C(k) = k - 273.15[/tex]
Required
Function from K to F
This implies that, we calculate F(k)
Given that:
[tex]F(c)= \frac{9}{5}c + 32[/tex]
Substitute c(k) for c
[tex]F(c(k))= \frac{9}{5}c(k) + 32[/tex]
Substitute: [tex]C(k) = k - 273.15[/tex]
[tex]F(c(k))= \frac{9}{5}(k - 273.15) + 32[/tex]
Hence:
[tex]F(k)= \frac{9}{5}(k - 273.15) + 32[/tex]
